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Direction (Q. 1-5) : Find the number in the place of question mark (?) in the following number series.
4, 13, 54, 273, 1642, ?
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Answer & Explanation
Answer : Option
D
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Explanation : |
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x 3 + 1, x 4 + 2, x 5 + 3 ......
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2 . |
3, 14, 66, 312, 1640, ?
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Answer & Explanation
Answer : Option
B
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Explanation : |
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+ 4 x 2, + 8 x 3, + 12 x 4
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3 . |
3, 8, 16, 15, 42, 29, 81, ?
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Answer & Explanation
Answer : Option
A
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Explanation : |
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The series is based on combination of two series. S1 = + 13, +26, +39 ...... and S2 = +7, +14, +21 .......
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4 . |
6, 42, 114, 258, 546, ?
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Answer & Explanation
Answer : Option
D
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Explanation : |
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+36, +72, +144, +288 .......
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5 . |
484, 729, 1024, 1369, 1764, ?
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Answer & Explanation
Answer : Option
C
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Explanation : |
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(22)2, (27)2, (32)2, (37)2 .........
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6 . |
Direction (Q. 6-10) : In each of these questions, two equations (I) and (II) are given. You have to solve both the equations and given answer.
I. x2 + 3x - 28 = 0 II. y2 - 11y + 28 = 0
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Answer & Explanation
Answer : Option
C
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Explanation : |
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I. x2 + 7x - 4x - 28 = 0
or, x(x + 7) - 4 (x + 7) = 0
or, (x - 4) (x + 7) = 0
∴ x = 4, -7
II. y2 - 11y + 28 = 0
or, y2 - 7y - 4y + 28 = 0
or, y (y - 7) - 4 (y - 7) = 0
or, (y - 4) (y - 7) = 0
∴ y = 4, 7
∴ x < y
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7 . |
I. 6x2 - 17x + 12 = 0 II. 6y2 - 7y + 2 = 0
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Answer & Explanation
Answer : Option
A
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Explanation : |
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I. 6x2 - 17x + 12 = 0
or, 6x2 - 9x - 8x + 12 = 0
or, 3x (2x - 3) - 4 (2x - 3) = 0
or, (3x - 4) (2x - 3) = 0
∴ x = 4/3, 3/2
II. 6y2 - 3y - 4y + 2 = 0
or, 3y (2y - 1) - 2 (2y - 1) = 0
or, (3y - 2) (2y - 1) = 0
∴ y = 2/3, 1/2
∴ x > y
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8 . |
I. x = √256/√576 II. 3y2 + y - 2 = 0
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Answer & Explanation
Answer : Option
B
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Explanation : |
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I. x = √256/√576
∴ x = 16/24 = 2/3
II. 3y2 + y - 2 = 0
or, 3y2 + 3y - 2y - 2 = 0
or, 3y (y + 1) - 2 (y + 1) = 0
or, (3y - 2) (y + 1) = 0
∴ y = 2/3, -1
∴ x > y
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9 . |
I. x2 = 64 II. y2 = 9y
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Answer & Explanation
Answer : Option
D
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Explanation : |
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I. x2 = 64
∴ x = + 8
II. y2 = 9y
or, y2 - 9y = 0
or, y (y - 9) = 0
∴ y = 0, 9
∴ no relationship can be established between x and y.
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10 . |
I. x2 + 6x - 7 = 0 II. 41y + 17 = 140
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Answer & Explanation
Answer : Option
C
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Explanation : |
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I. x2 + 6x - 7 = 0
or, x2 + 7x - 7 = 0
or, x(x + 7) - 1 (x + 7) = 0
or, (x - 1) (x + 7) = 0
∴ x = 1, -7
II. 41y + 17 = 140
or, 41y = 140 - 17 = 123
∴ y = 123/41 = 3
∴ x < y
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