1 . 
Direction (Q. 15): Informations I and II are given about the problem.
What is the age of the teacher ?
I The strength of the class, inclusive of the teacher, is 26.
II The ayerage age of the class, inclusive of the teacher's age, is 15 years.


Answer & Explanation
Answer : Option
D


Explanation : 

From I & II, we find the total age of the class = 26 x 15 = 390 years. We can't find the age of the teacher from these two statements.






2 . 
What is the compound interest earned by Suresh on Rs 3600 ?
I The amount is given for two years on interest.
II The amount becomes eight times in three years.


Answer & Explanation
Answer : Option
C


Explanation : 

From statement I, we get time, ie 2 years. for which compound interest is to be calculated
From ll.
8P = P [(1 + 8/100)^{3}]
= 8 = (1 + 2/100)^{3}
= 2^{3} = 1 + r/100 = 4 = 100%
statement I & II both are necessary to calculate the compound interest on the given sum.






3 . 
Find the price of commodities A and B.
I 3 kg of A and 4 kg of B cost Rs 80.
II If the price of A rose by 25% and that of B fell by 20%, the above cost would become Rs 91.


Answer & Explanation
Answer : Option
C


Explanation : 

From statement I we get
3A + 4B = 80 ......(i)
A  cfost of commodity A in rupees
B  cost of commodity B in rupees
3A x 125/100 + 4B x 80/100 = 91
= 15A/4 + 16B/5 = 91
75A + 64B = 1820 .......(ii)
Solving these two equations, by equating A in both the equations, we find A = Rs. 20,
B = Rs. 5
Both the statements are required to solve the question.






4 . 
What will be the ratio of the perimeters of a square and a rectangle ?
I The hypotenuse of the square is b metre.
II The area of the rectangle is twothirds of the area of a circle of radius b/3 metre.


Answer & Explanation
Answer : Option
D


Explanation : 

From Statement I. side of the square = b/2
Therefore, perimeter of the square = 4 b/2 = 22b
From statement II, area of the circle
= PI(b/3)2 = IB
I  length of recentagle
b  breadth of rectangle
We can't calculate 2(1 + b) as required from the given value of Ib






5 . 
In how many days can Gautam alone complete a work ?
I Gautam works at twice the pace of Mukund and at onefourth the pace of Nikunj.
II All of them can finish the work in 18 days.


Answer & Explanation
Answer : Option
C


Explanation : 

Let Gautam complete the work in x days.
From statement I, Mukund completes the some work in 2x days and Nikunj completes it
x/4 days,
Also, from statement II, we get they complete
1/18 work in 1 day.
= 1/x + 1/2x + 4/x = 1/18
= 11/2x = 1/18 = x = 99 days.
Hence both statements are needed to solve the question.






6 . 
Direction (Q. 610): Answer the following questions on the basis of the information given below. The table shows the wages of 6 labourers in six months.
Labourer Month 
A 
B 
C 
D 
E 
F 
I 
05 
12 
15 
10 
6..5 
18 
II 
08 
10 
13 
10.5 
8.5 
18.5 
III 
7.5 
11 
12.5 
2.5 
12.5 
19 
IV 
12.5 
09 
13.5 
3.5 
13.5 
19.5 
V 
13.5 
08 
14.5 
4.5 
14 
20 
VI 
14 
07 
16 
8.5 
16.5 
20.5 
Which labourer(s) got a gradual increase in wage over the months ?


Answer & Explanation
Answer : Option
C


Explanation : 

By looking at the table, we can sector that only for labours E & F there is a graduate increase in the wages over the months.






7 . 
In which month has wages of each labourer increased from his previous month's wages ?


Answer & Explanation
Answer : Option
D


Explanation : 

By interview the table we can conclusion that there is no such month in which there is an increase in the wages all the labourers over their previous month's wages.






8 . 
Which labourer has the maximum percentage increase in wages (in any month) from his first month's wages ?


Answer & Explanation
Answer : Option
D


Explanation : 


A 
B 
C 
D 
E 
F 
1st month 
5 
12 
15 
10 
6.5 
18 
The month in which wages is maximum 
14 IV 
12 I 
16 VI 
10.5 II 
16.5 VI 
20.5 VI 
% increase in the wages 
180% 
0% 
6.66% 
5% 
154% 
14% 






9 . 
In which month(s), the average wages"of all the labourer, the decreased from their previous month's average wages ?


Answer & Explanation
Answer : Option
A


Explanation : 

Month 
I 
II 
III 
IV 
V 
VI 
Total wages 
66.5 
68.5 
65 
71.5 
74.5 
82.5 
By viewing the table, we can conclude that in month III total wages of all the labourers has decreased w.r.t. their wages of previous months, hence the average wages will also decreases in the same month.






10 . 
Which labourer has the minimum average wages over the months ?


Answer & Explanation
Answer : Option
B


Explanation : 

We count the wages of the labourers, by observing that the least number of doubledigit wages lies in which column. It is for D. Also, we can do this by calculating their total wages.
Labourer 
A 
B 
C 
D 
E 
F 
Total Wages 
60.5 
57 
84.5 
39.5 
71.5 
115.5 
Averate wages = Total wages






