There are 27 elements in series I. Among which, the numbers of letters, symbols and digits/numbers are 8, 8 and 11 respectively. When the changes occur, the symbols are replaced by letters. Hence, the number of letters becomes 16 (= 8 + 8).
If every third element of series II is omitted, starting from P (omit P first), and the order of the remaining elements is left unaltered, then which of the following elements will be exactly midway between the third element from left and the ninth element from right in the new series obtained after the above changing ?
In the series I if the first element from left interchanges place with the fifteenth element from left, second with sixteenth, third with seventeenth, and so on, then which of the following elements will be sixth to the left of the ninth element from the right end of series I ?
Sixth to the left of ninth element from right end of series I, is (6 + 9 =) 15th element from right end of the series I, ie M. After interchanging, M will be replaced by A. Hence, the required element is A.
Direction (Q. 6-10): In a certain code, the symbol for 0 is • and for 1 is ∆. There are no other symbols for all other numbers greater than one. The numbers greater than 1 are to be written only by using the two symbols given above. The value of the symbol for 1 double itself every time it shifts one place to the left, study the following examples :
0 is written as •
1 is written as ∆
2 is written as ∆•
3 is written as ∆∆
4 is written as ∆ •• and so on.